newton second law and problem based on it questions with solutions

Showing 1–10 of 127 questions

• MCQeasyNewtons law of motion and Frictionnewton second law and problem based on it

  A 10 kg block rests on a rough horizontal surface, μ=0.5. If a horizontal force of 100 N acts on it, find acceleration (g=10 m s⁻²).

  Options

  • Option A

    10 m s⁻²

  • Option B

    5 m s⁻²

  • Option C

    15 m s⁻²

  • Option D

    0.5 m s⁻²

  Check answerShow answer

  AIPMT 2002NEET

  Open question & full solution →
• MCQmediumNewtons law of motion and Frictionnewton second law and problem based on it

  A rigid ball of mass m strikes a rigid wall as shown at 60° to the normal, and rebounds symmetrically without losing speed v. The impulse imparted by the wall is:

  

  Options

  • Option A

    mv

  • Option B

    2mv

  • Option C

    mv/2

  • Option D

    mv/3

  Check answerShow answer

  NEET Phase-II 2016

  Open question & full solution →
• MCQeasyNewtons law of motion and Frictionnewton second law and problem based on it

  A particle of mass m has position vector r = a(cosωt, sinωt). The direction of the net force on the particle is:

  Options

  • Option A

    Opposite to the direction of r

  • Option B

    Opposite to the direction of linear momentum P

  • Option C

    Opposite to the direction of angular momentum L

  • Option D

    Opposite to the direction of L×P

  Check answerShow answer

  JEE Mains 2025 4 April Morning Shift

  Open question & full solution →
• MCQmediumNewtons law of motion and Frictionnewton second law and problem based on it

  A small groove is cut in a fixed 30° inclined surface. In plan view the groove has OA=4 m and OB=3 m as shown. A steel ball starts from rest at O and slides along the groove. Take g=10 m s⁻². Its speed at A is:

  

  Options

  • Option A

    √40 m s⁻¹

  • Option B

    √20 m s⁻¹

  • Option C

    √10 m s⁻¹

  • Option D

    √15 m s⁻¹

  Check answerShow answer

  JEE MainsNEET

  Open question & full solution →
• MCQdifficultNewtons law of motion and Frictionnewton second law and problem based on it

  Five persons A,B,C,D,E pull a 100 kg cart. With all five, acceleration is 3 m s⁻² east. If A stops, acceleration is 1 m s⁻² west. If only B stops, acceleration is 24 m s⁻² north. What is the cart acceleration when only A and B pull in their original directions?

  Options

  • Option A

    26 m s⁻²

  • Option B

    3√71 m s⁻²

  • Option C

    25 m s⁻²

  • Option D

    30 m s⁻²

  Check answerShow answer

  JEE MainsJEE Advanced

  Open question & full solution →
• MCQmediumNewtons law of motion and Frictionnewton second law and problem based on it

  A balloon of mass m is descending with downward acceleration a (a<g). How much mass must be removed so that it ascends with acceleration a? Assume buoyant force stays constant.

  Options

  • Option A

    2ma/(g+a)

  • Option B

    2ma/(g-a)

  • Option C

    ma/(g+a)

  • Option D

    ma/(g-a)

  Check answerShow answer

  AIPMT 2014NEET

  Open question & full solution →
• MCQeasyNewtons law of motion and Frictionnewton second law and problem based on it

  At any instant the velocity of a particle of mass 500 g is (2t î + 3t² ĵ) m s⁻¹. If the force acting on the particle at t = 1 s is (î + xĵ) N, then the value of x is:

  Options

  • Option A

    2

  • Option B

    6

  • Option C

    3

  • Option D

    4

  Check answerShow answer

  JEE Mains8 April 2023Shift 1Morning Shift

  Open question & full solution →
• MCQeasyNewtons law of motion and Frictionnewton second law and problem based on it

  A force of 10 N produces acceleration 1 m s⁻² in a body. Find its mass.

  Options

  • Option A

    15 kg

  • Option B

    20 kg

  • Option C

    10 kg

  • Option D

    5 kg

  Check answerShow answer

  AIPMT 1996NEET

  Open question & full solution →
• MCQmediumNewtons law of motion and Frictionnewton second law and problem based on it

  A 20 kg monkey climbs a vertical rope that can safely support a hanging mass of 25 kg but breaks for larger loads. Using g=10 m s⁻², find maximum upward acceleration the monkey can have without breaking the rope.

  Options

  • Option A

    5 m s⁻²

  • Option B

    10 m s⁻²

  • Option C

    25 m s⁻²

  • Option D

    2.5 m s⁻²

  Check answerShow answer

  AIPMT 2003NEET

  Open question & full solution →
• Multi-correctdifficultNewtons law of motion and Frictionnewton second law and problem based on it

  Blocks of 5 kg, 3 kg and 2 kg lie in contact on a smooth floor. A 200 N force acts rightward on the 5 kg block and 50 N leftward on the 2 kg block. Which statements are correct?

  

  Select all that apply

  • Option A

    Common acceleration is 15 m s⁻².

  • Option B

    The two contact forces are 120 N and 80 N.

  • Option C

    Net forces on the blocks are 75 N, 45 N and 30 N.

  • Option D

    The common acceleration is 25 m s⁻².

  Check answerShow answer

  JEE MainsJEE Advanced

  Open question & full solution →