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Pseudo force related problem questions with solutions
Practice Newtons law of motion and Friction for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
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- MCQmediumNewtons law of motion and Friction
A bob hangs from a string over a pulley inside a car accelerating horizontally with acceleration a. A person in the car pulls the other end of the string downward with acceleration a relative to the car. The string tension is:

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A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t₁ when the elevator is stationary and t₂ when it moves with uniform velocity. Then:
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An Atwood machine with masses 3m and m is suspended inside a lift accelerating vertically upward with acceleration g/2. The acceleration of 3m relative to the lift is:
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- MCQmediumNewtons law of motion and Friction
A 4 kg body appears to weigh 4.8 kg-wt in a moving lift. The lift acceleration is:
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A wedge of mass M is pushed horizontally so that a small block of mass m remains stationary relative to it. The wedge angle is β. The required horizontal force P is:

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A plumb line hangs from the ceiling of a car accelerating horizontally with acceleration a. Its angle with the vertical is:
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A wedge of mass M and inclination α rests on a smooth horizontal floor. A small block of mass m is released from rest on its smooth inclined face. The magnitude of horizontal acceleration of the wedge is:
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- MCQmediumNewtons law of motion and Friction
A block lies on the floor of an elevator initially at rest. The elevator suddenly accelerates downward at 13 m s⁻². Take g=10 m s⁻². What is the separation between block and floor after 0.2 s?
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A smooth wedge of inclination 37° rises towards the right and accelerates horizontally towards the right with a = 10 m/s². A 2 kg block remains in contact with the inclined surface. Take g = 10 m/s², sin37° = 3/5 and cos37° = 4/5. The normal reaction exerted by the wedge on the block is:
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- MCQmediumNewtons law of motion and Friction
A wedge of mass 10 kg rests on a frictionless horizontal surface. Its smooth inclined face makes an angle of 37° with the horizontal. A 2 kg block is placed at the highest point of the incline and is initially at rest relative to the wedge. At t = 0, a constant horizontal force of 24 N is applied to the wedge toward the right. Taking tan37° = 3/4 and g = 10 m·s⁻², approximately how much time does the block take to slide 8.8 m down the incline relative to the wedge?

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JEE Mains 2026 5 April Morning Shift
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