Power questions with solutions

Showing 1–10 of 47 questions

• MCQmediumWork , Power and EnergyPower

  A particle of mass 10/7 kg moves along +x with initial speed 1 m/s at x=0. The graph of power delivered versus position x is shown. Find its speed at x=10 m.

  

  Options

  • Option A

    4 m/s

  • Option B

    2 m/s

  • Option C

    3√2 m/s

  • Option D

    10/√3 m/s

  Check answerShow answer

  JEE Advanced

  Open question & full solution →
• Multi-correctmediumWork , Power and EnergyPower

  For a particle, the instantaneous net power is $P_net.$ Which statements are correct?

  Select all that apply

  • Option A

    $P_net$ = dK/dt

  • Option B

    If $P_net$ > 0, speed is increasing at that instant

  • Option C

    If $P_net$ = 0, acceleration must be zero

  • Option D

    For uniform circular motion, net power is zero

  Check answerShow answer

  JEE MainsNEETJEE Advanced

  Open question & full solution →
• MCQmediumWork , Power and EnergyPower

  A particle of mass M starting from rest undergoes uniform acceleration. If the speed acquired in time T is v, the power delivered to the particle is:

  Options

  • Option A

    Mv²/T

  • Option B

    Mv²/(2T²)

  • Option C

    Mv²/T²

  • Option D

    Mv²/(2T)

  Check answerShow answer

  NEET 2021

  Open question & full solution →
• MCQmediumWork , Power and EnergyPower

  A particle moves unidirectionally on a horizontal plane under a constant-power energy source. Which displacement-time graph describes the motion? Image

  Options

  • Option A

    
  • Option B

    
  • Option C

    
  • Option D

    

  Check answerShow answer

  JEE Mains

  Open question & full solution →
• MCQmediumWork , Power and EnergyPower

  A machine supplies constant power k to a mass m initially at rest. What force acts on the mass at time t?

  Options

  • Option A

    √(mk/2) t⁻¹ᐟ²

  • Option B

    √(mk) t⁻¹ᐟ²

  • Option C

    √(2mk) t⁻¹ᐟ²

  • Option D

    ½√(mk) t⁻¹ᐟ²

  Check answerShow answer

  AIPMT Cancelled 2015NEET

  Open question & full solution →
• MCQmediumWork , Power and EnergyPower

  A block of mass m is being pulled up the rough inclined by an agent delivering constant power P. The coefficient of friction between the block and the inclined is µ. The maximum speed of the block during the course of ascent is:

  

  Options

  • Option A

    v=P/[mg(sinθ+µcosθ)]

  • Option B

    v=P/[mg(sinθ-µcosθ)]

  • Option C

    v=2P/[mg(sinθ-µcosθ)]

  • Option D

    v=3P/[mg(sinθ-µcosθ)]

  Check answerShow answer

  JEE Advanced

  Open question & full solution →
• NumericmediumWork , Power and EnergyPower

  A body of mass 1 kg begins to move under the action of a time dependent force $\overrightarrow{F}$ = (tî + 3t²ĵ) N, where î and ĵ are the unit vectors along x and y axis. The power developed by above force, at the time t = 2s. will be _______W.

  Your answer

  Check answerShow answer

  JEE Mains24 January 2023Shift 2Evening Shift

  Open question & full solution →
• MCQeasyWork , Power and EnergyPower

  A motor lifts a mass m vertically upward with constant speed v. If an additional constant downward resistive force f acts on the mass, the power delivered by the motor is:

  Options

  • Option A

    mgv

  • Option B

    (mg-f)v

  • Option C

    (mg+f)v

  • Option D

    fv

  Check answerShow answer

  JEE MainsNEETJEE Advanced

  Open question & full solution →
• MCQmediumWork , Power and EnergyPower

  A 4 kg particle moves along x with position x(t)=t+2t³ (SI units). Find (i) kinetic energy K(t); (ii) force F(t); (iii) power P(t); (iv) work done from t=0 to 2 s.

  Options

  • Option A

    K=2+24t²+72t⁴ J; F=48t N; P=48t+288t³ W; W₀→₂=1248 J

  • Option B

    K=2+12t²+36t⁴ J; F=24t N; P=24t+144t³ W; W=624 J

  • Option C

    K=1+24t²+72t⁴ J; F=48t² N; P=96t³ W; W=1248 J

  • Option D

    K=2+24t²+36t⁴ J; F=24t N; P=48t+144t³ W; W=624 J

  Check answerShow answer

  JEE Advanced

  Open question & full solution →
• MCQmediumWork , Power and EnergyPower

  An object of mass 1000 g experiences a time-dependent force F = (2t, 3t²) N. Assuming zero initial velocity, the instantaneous power generated by the force at time t is:

  Options

  • Option A

    (2t²+3t³) W

  • Option B

    (2t²+18t³) W

  • Option C

    (3t³+5t⁵) W

  • Option D

    (2t³+3t⁵) W

  Check answerShow answer

  JEE Mains 2025 7 April Morning Shift

  Open question & full solution →