The velocity of a particle executing SHM varies with displacement x as 4v² = 50 - x². The time period of oscillations is x₀/7 s. The value of x₀ i s ______. [Take π = 22/7]

Question

G1 Physics · Accepted Answer

Rewrite as v² = (1/4)(50-x²). Comparing with v² = ω²(A²-x²), we get ω² = 1/4 and ω = 1/2 rad s⁻¹. Hence T = 2π/ω = 4π = 88/7 s. Therefore x₀ = 88.