Nucleus A has Z = 17 and equal numbers of protons and neutrons. Its binding energy per nucleon is 1.2 MeV. Nucleus B has Z = 12, total nucleons 26 and binding energy per nucleon 1.8 MeV. Find the difference between the total binding energy of B and A, in MeV.
Physics · Nuclear physics · Nucles and its density radius and mass defect ,binding energy and its curve
JEE Mains 1st Feb Evening Shit 2023

Question

Nucleus A has Z = 17 and equal numbers of protons and neutrons. Its binding energy per nucleon is 1.2 MeV. Nucleus B has Z = 12, total nucleons 26 and binding energy per nucleon 1.8 MeV. Find the difference between the total binding energy of B and A, in MeV.

Physics · Nuclear physics · Nucles and its density radius and mass defect ,binding energy and its curve

JEE Mains 1st Feb Evening Shit 2023

G1 Physics · Accepted Answer

For nucleus A: Number of protons = 17 Number of neutrons = 17 Mass number: A = 17 + 17 = 34 Total binding energy of A: B.E. of A = 34 × 1.2 = 40.8 MeV For nucleus B: Mass number = 26 Total binding energy of B: B.E. of B = 26 × 1.8 = 46.8 MeV Required difference: 46.8 - 40.8 = 6 MeV Final answer: 6.