A particle moves for 4 s each with velocities +6 m s⁻¹, +12 m s⁻¹ and −3 m s⁻¹. Find average speed − magnitude of average velocity, in m s⁻¹.

Question

G1 Physics · Accepted Answer

Total distance = 4(6+12+3) = 84 m. Total displacement = 4(6+12−3) = 60 m. Total time = 12 s. Average speed = 84/12 = 7 m s⁻¹. Magnitude of average velocity = 60/12 = 5 m s⁻¹. Required difference = 7−5 = 2 m s⁻¹.