A 10 kg mass is suspended by a 4 m rope from the ceiling. A horizontal force F is applied at the midpoint so that the upper half of the rope makes 45° with the vertical while the mass remains at rest. Take g=10 m s⁻². F is:
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Question

A 10 kg mass is suspended by a 4 m rope from the ceiling. A horizontal force F is applied at the midpoint so that the upper half of the rope makes 45° with the vertical while the mass remains at rest. Take g=10 m s⁻². F is:

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G1 Physics · Accepted Answer

The lower half is vertical and carries 100 N. At the midpoint, the upper-string vertical component balances 100 N. With 45°, its horizontal component equals its vertical component, so F=100 N.