A ball is horizontally projected with a speed v from the top of a plane inclined at an angle 45° with the horizontal. How far from the point of projection will the ball strike the plane?
Select all that apply

Question

A ball is horizontally projected with a speed v from the top of a plane inclined at an angle 45° with the horizontal. How far from the point of projection will the ball strike the plane?

G1 Physics · Accepted Answer

For horizontal projection, x = vt and vertical drop y = ½gt². The 45° plane satisfies y = x, so ½gt² = vt and t = 2v/g. Thus horizontal distance x = 2v²/g. The distance along the 45° plane is x sec45° = 2√2v²/g. Hence option D.