Position-time graph of a particle of mass 2 kg is shown in figure. Total work done on the particle from t = 0 to t = 4s is

Question

G1 Physics · Accepted Answer

Net work equals change in kinetic energy. The slopes of the x-t graph at t=0 and t=4 s have equal magnitude, so initial and final speeds are equal. Hence ΔK=0 and total work is 0 J.