A simple harmonic motion having an amplitude A and time period T is represented by the equation: y = 5 sin π(t + 4) m. Then the values of A (in m) and T (in s) are :
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Question

A simple harmonic motion having an amplitude A and time period T is represented by the equation: y = 5 sin π(t + 4) m. Then the values of A (in m) and T (in s) are :

G1 Physics · Accepted Answer

Compare y=5 sin[π(t+4)] with y=A sin(ωt+φ). Thus A=5 m and ω=π rad s⁻¹. Therefore T=2π/ω=2 s. Correct answer: A.