A simple harmonic motion is y = 5[sin(3πt) + √3 cos(3πt)]. What is the amplitude (in cm) if y is in m?
Physics · Simple Harmonic Motion
JEE Mains Advanced

Question

A simple harmonic motion is y = 5[sin(3πt) + √3 cos(3πt)]. What is the amplitude (in cm) if y is in m?

G1 Physics · Accepted Answer

Combine the two same-frequency terms: amplitude=5√(1²+(√3)²)=5√4=10 m. Converting to centimetres gives 1000 cm.