A particle undergoing SHM has displacement x(t) = A sin(πt/90). The ratio of kinetic to potential energy at t = 210 s is:
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Question

A particle undergoing SHM has displacement x(t) = A sin(πt/90). The ratio of kinetic to potential energy at t = 210 s is:

G1 Physics · Accepted Answer

At t=210 s, phase θ=πt/90=7π/3, equivalent to π/3. For x=A sinθ, U/E=sin²θ=3/4 and K/E=cos²θ=1/4. Thus K/U=(1/4)/(3/4)=1/3. Correct option: 3.