A thin tube is bent into a vertical circle of radius r. Equal volumes of immiscible liquids of densities ρ₁ and ρ₂ (ρ₁ > ρ₂) fill half the circle. Find the angle θ between the radius through the common interface and the vertical.
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Question

A thin tube is bent into a vertical circle of radius r. Equal volumes of immiscible liquids of densities ρ₁ and ρ₂ (ρ₁ > ρ₂) fill half the circle. Find the angle θ between the radius through the common interface and the vertical.

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G1 Physics · Accepted Answer

Step 1: Use hydrostatic equilibrium, P₂−P₁ = ρgΔh; in an accelerating fluid replace g by the effective acceleration where required. Step 2: Equate pressures at the same horizontal level or integrate pressure over the stated surface. Applying these relations to the given data gives D: None of these. Final answer: D.