In the shown figure, the total acceleration of a particle moving clockwise in a circle of radius R = 2.5 m is 15 m s⁻². The total acceleration makes an angle of 30° with the inward radial direction. Find the speed of the particle.

Question

G1 Physics · Accepted Answer

Step 1: The radial component of acceleration gives the centripetal acceleration: aᵣ = a cos 30° = 15(√3/2) m s⁻². Step 2: v²/R = aᵣ, so v² = (2.5)(15)(√3/2) ≈ 32.48 m² s⁻². Step 3: v = √32.48 ≈ 5.70 m s⁻¹. Correct answer: C. The uploaded book misprints R = 0.2 m; the original NEET Phase-II 2016 question states R = 2.5 m.