If kinetic energy of a body is increased by 300%, what is the percentage increase in its momentum?
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If kinetic energy of a body is increased by 300%, what is the percentage increase in its momentum?

G1 Physics · Accepted Answer

Step 1 — Principle: At fixed momentum, kinetic energy can be written K = p²/(2m). Step 2 — Working: A 300% increase means Kf=4Ki. Step 3 — Working: At fixed mass p=√(2mK), so pf/pi=√4=2. Step 4 — Working: Increase=(2−1)×100%=100%. Correct answer: A — 100%.