At what depth d below Earth’s surface does acceleration due to gravity become 1/n of its surface value (Earth radius R)?
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Question

At what depth d below Earth’s surface does acceleration due to gravity become 1/n of its surface value (Earth radius R)?

G1 Physics · Accepted Answer

Step 1: For uniform density g(d)=g₀(1−d/R). Step 2: Setting g(d)=g₀/n gives 1−d/R=1/n, hence d=R(n−1)/n. Final answer: B — R(n−1)/n.