At what height above Earth’s surface does a body’s weight become 1/16 of its surface weight (Earth radius R)?
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Question

At what height above Earth’s surface does a body’s weight become 1/16 of its surface weight (Earth radius R)?

G1 Physics · Accepted Answer

Step 1: Use W(h)/W₀=[R/(R+h)]²=1/16. Step 2: Therefore R/(R+h)=1/4, giving R+h=4R and h=3R. Final answer: C — 3R.