Irodov Level physics questions with solutions

Showing 1–10 of 40 questions

• MCQeasyGravitationAcceleration Due to Gravity & Escape Velocity

  At a small height h above Earth's surface, g equals its value at depth d below the surface. For h, d≪R and uniform Earth density:

  Options

  • Option A

    d=h

  • Option B

    d=2h

  • Option C

    h=2d

  • Option D

    d=4h

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• A/RmediumGravitationSatellites, Orbital Motion & Kepler’s Laws

  Evaluate the following statements.

  Assertion

  Assertion (A): A satellite in a larger circular orbit has greater total mechanical energy than the same satellite in a smaller circular orbit.

  Reason

  Reason (R): Circular-orbit energy E=-GMm/(2r) becomes less negative as orbital radius increases.

  Options

  • Option A

    Both A and R are true and R is the correct explanation of A.

  • Option B

    Both A and R are true but R is NOT the correct explanation of A.

  • Option C

    A is true but R is false.

  • Option D

    A is false but R is true.

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  JEE AdvancedIrodov Level

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• Multi-correcteasyGravitationGravitation, Gravitational Field & Potential Energy

  A thin uniform spherical shell has mass M and radius R. Which statements are correct for points inside the shell?

  Select all that apply

  • Option A

    Gravitational field is zero everywhere

  • Option B

    Gravitational potential is constant

  • Option C

    Potential equals -GM/R

  • Option D

    Potential is zero everywhere

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• NumericmediumGravitationGravitation, Gravitational Field & Potential Energy

  A thin ring of mass M and radius R produces maximum gravitational field on its axis at x=R/√n. Find n.

  Your answer

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  JEE AdvancedIrodov Level

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• NumericeasyGravitationGravitation, Gravitational Field & Potential Energy

  Four equal masses m are placed at the corners of a square of side a. If the magnitude of gravitational potential at the centre is n√2 Gm/a, find n.

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  JEE AdvancedIrodov Level

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• Multi-correctmediumGravitationSatellites, Orbital Motion & Kepler’s Laws

  A satellite moves in an elliptical orbit around a planet. Which statements are correct?

  Select all that apply

  • Option A

    Areal velocity is constant

  • Option B

    Speed is maximum at perigee

  • Option C

    Total mechanical energy is constant

  • Option D

    Angular speed about the planet is constant

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• NumericeasyGravitationAcceleration Due to Gravity & Escape Velocity

  At height h=R above Earth's surface, the acceleration due to gravity is g₀/n, where g₀ is surface gravity. Find n.

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• A/RmediumGravitationGravitation, Gravitational Field & Potential Energy

  Evaluate the following statements.

  Assertion

  Assertion (A): Gravitational potential may be non-zero at a point where gravitational field is zero.

  Reason

  Reason (R): Zero gravitational field means the spatial derivative of potential is zero at that point; it does not require the potential itself to be zero.

  Options

  • Option A

    Both A and R are true and R is the correct explanation of A.

  • Option B

    Both A and R are true but R is NOT the correct explanation of A.

  • Option C

    A is true but R is false.

  • Option D

    A is false but R is true.

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• Multi-correcteasyGravitationGravitation, Gravitational Field & Potential Energy

  A thin uniform spherical shell has mass M and radius R. A particle is moved from its centre O to a point P on its surface. Which statements are correct?

  Select all that apply

  • Option A

    Gravitational field is zero at every point of the path inside the shell

  • Option B

    Gravitational potential remains constant throughout the path

  • Option C

    Work done by gravitational force is zero

  • Option D

    Potential at the centre is more negative than at the surface

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• MCQmediumGravitationGravitation, Gravitational Field & Potential Energy

  A uniform solid sphere has mass M and radius R. A narrow tunnel is drilled through its centre. A particle is released from rest at the surface. Its speed at the centre is:

  Options

  • Option A

    √(GM/R)

  • Option B

    √(2GM/R)

  • Option C

    √(GM/(2R))

  • Option D

    √(3GM/(2R))

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