JEE Advanced 2023 physics questions with solutions

Showing 1–10 of 25 questions

• MCQmediumThermodynamics

  One mole of an ideal gas starts at temperature T₁ and volume V₀ and expands adiabatically to a common final state at temperature T₃ and volume 5V₀. Another mole of the same gas starts at temperature T₂ and volume V₀ and expands isothermally to the same final state. If γ=Cₚ/Cᵥ, find T₁/T₂.

  Options

  • Option A

    $5^{\gamma-1}$

  • Option B

    $5^{1-\gamma}$

  • Option C

    $5^{\gamma}$

  • Option D

    $5^{1+\gamma}$

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• NumericmediumSimple Harmonic Motion

  Masses 20 g and 30 g are fixed at the ends of a rigid massless rod of length 10 cm. The system is suspended by a torsion wire attached at its centre of mass. Torsional constant is 1.2×10⁻⁸ N m rad⁻¹. If angular frequency is n×10⁻³ rad s⁻¹, find n.

  

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• NumericmediumThermodynamics

  A closed container contains a homogeneous mixture of two moles of an ideal monatomic gas (γ=5/3) and one mole of an ideal diatomic gas (γ=7/5). The mixture does 66 J of work when heated at constant pressure. Find the change in internal energy, in joules.

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• MCQmediumGravitationSatellites, Orbital Motion & Kepler’s Laws

  Two satellites P and Q move in circular orbits around Earth of radius R. Satellite P is at height R/3 above the surface. If the ratio of gravitational acceleration at P to that at Q is 36/25, find the height of satellite Q.

  Options

  • Option A

    3R/5

  • Option B

    R/6

  • Option C

    6R/5

  • Option D

    5R/6

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• NumericmediumProperties of solid and fluid

  Air in a sealed container is compressed isothermally from V₀ to (100/101)V₀. A capillary of radius 0.1 mm passes through the piston and is open to atmosphere. Given T = 0.075 N m⁻¹, Pₐₜₘ = 10⁵ Pa, g = 10 m s⁻², liquid density 10³ kg m⁻³ and zero contact angle, find capillary rise h in cm. Image

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• MatchmediumElectromagnetic Induction

  A thin conducting rod MN of mass 20 g, length 25 cm and resistance 10 Ω is held on frictionless vertical conducting rails in uniform B₀=4 T perpendicular to the plane. It is released from rest. Take g=10 m s⁻² and e⁻¹=0.4. Match List-I with List-II.

  

  List 1

  1. (P) Induced emf at t=0.2 s (V)

  2. (Q) Magnetic force at t=0.2 s (N)

  3. (R) Heat power at t=0.2 s (W)

  4. (S) Terminal speed (m s⁻¹)

  5. .

  List 2

  1. (1) 0.07

  2. (2) 0.14

  3. (3) 1.20

  4. (4) 0.12

  5. (5) 2.00

  Options

  • Option A

    P → 5, Q → 2, R → 3, S → 1

  • Option B

    P → 3, Q → 1, R → 4, S → 5

  • Option C

    P → 4, Q → 3, R → 1, S → 2

  • Option D

    P → 3, Q → 4, R → 2, S → 5

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• ParagraphmediumWave Motion

  S₁ and S₂ are identical sound sources of frequency 656 Hz. S₁ is at O. S₂ moves anticlockwise with speed 4√2 m s⁻¹ on a circular path about O. P and R are diametrically opposite and Q is midway on the arc as shown; a detector is at P. Speed of sound is 324 m s⁻¹.

  

  Sub-question 1

  When only S₂ is emitting sound and it is Q, the frequency of sound measured by the detector in Hz is [blank].

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  Sub-question 2

  Consider both sources emitting sound. When S₂ is at R and S₁ approaches the detector with a speed 4 m s⁻¹,the beat frequency measured by the detector is [blank]Hz.

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• NumericmediumAtomic Structure and X-rays

  A hydrogen-like atom has atomic number Z. Photons from its n=4→3 transition cause photoemission from a metal. Kₘₐₓ=1.95 eV and threshold wavelength is 310 nm. Given hc=1240 eV·nm and Rhc=13.6 eV, find Z.

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• MCQmediumCapacitor

  A container has base 50 cm × 5 cm and height 50 cm. Two opposite conducting walls each have area 50 cm × 50 cm; the other walls are thin and non-conducting. A liquid of dielectric constant 3 is poured in at 250 cm³ s⁻¹. Find the capacitance after 10 s. Use ε₀ = 9×10⁻¹² C² N⁻¹ m⁻² and neglect the non-conducting walls.

  

  Options

  • Option A

    27 pF

  • Option B

    63 pF

  • Option C

    81 pF

  • Option D

    135 pF

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• MCQmediumElectrostaticelectric dipole and dipole moment

  An electric dipole is formed by two charges +q and -q located in xy-plane at (0, 2) mm and (0, -2) mm, respectively, as shown in the figure. The electric potential at point P(100, 100) mm due to the dipole is V₀. The charges +q and -q are then moved to the points (-1, 2) mm and (1, -2) mm, respectively. What is the value of electric potential at P due to the new dipole ?

  

  Options

  • Option A

    V₀ /4

  • Option B

    V₀ /2

  • Option C

    $\frac{V_{\omicron}}{\sqrt2}$

  • Option D

    3V₀ /4

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