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Acceleration and Avg acceleration questions with solutions
Practice Kinematics Part-1 (one dimension) for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
Showing 1–10 of 77 questions
- MCQmediumKinematics Part-1 (one dimension)
The position of a particle moving along the x-axis is:

Which description is correct?
Options
JEE MainsNEET
Open question & full solution → - MCQdifficultKinematics Part-1 (one dimension)
A particle moves along the x-axis according to x = ut e⁻ᵏᵗ, where u, k>0. After its first reversal of direction, the particle again gains speed and subsequently slows down. The maximum speed attained after this reversal and the corresponding position are:
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JEE MainsJEE Advanced
Open question & full solution → - MCQmediumKinematics Part-1 (one dimension)
A particle moves such that its displacement is s=t³-6t²+3t+4 m. Its velocity at the instant when its acceleration is zero is:
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JEE MainsNEET
Open question & full solution → - MCQeasyKinematics Part-1 (one dimension)
A particle has v(0)=1 m s⁻¹ and a = 12t² - 6t. At the non-zero instant at which acceleration vanishes, its velocity is:
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JEE MainsNEET
Open question & full solution → - MatchdifficultKinematics Part-1 (one dimension)
The position of a particle along x-axis is x=(2t³-21t²+60t) m. Match Column-I with Column-II.
List 1
A.Velocity of particle is zero
B. Acceleration of particle is zero
C. Acceleration of particle is negative
D. Velocity of particle is towards the origin
.
List 2
p.2 s
q. 3 s
r. 3.5 s
s. 4 s
t. 5 s
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JEE MainsJEE Advanced
Open question & full solution → - MCQmediumKinematics Part-1 (one dimension)
A particle starts from rest and obeys dv/dt = α-βv, where α,β>0. Find the displacement by the time its speed becomes half of its terminal speed.
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JEE MainsNEET
Open question & full solution → - MCQmediumKinematics Part-1 (one dimension)
Acceleration varies as a = A t(T-t) during 0≤t≤T. The average acceleration in this interval is:
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JEE MainsNEET
Open question & full solution → - Multi-correctmediumKinematics Part-1 (one dimension)
The acceleration of a moving body at any ‘t’ is given by a = (4t)î + (3t²)ĵ m/sec². If u = 0 then find the velocity (in m/s) of the particle at 4 sec.
Select all that apply
JEE Advanced
Open question & full solution → - MCQmediumKinematics Part-1 (one dimension)
A particle starts from rest at x=0 and has acceleration a=a₀cosωt. At t=π/ω, its velocity and displacement are respectively:
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JEE MainsNEET
Open question & full solution → - MCQmediumKinematics Part-1 (one dimension)
Position is x = At³ + Bt² + Ct + D. The average acceleration between t=t₁ and t=t₂ is:
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JEE MainsNEET
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