Position is x = At³ + Bt² + Ct + D. The average acceleration between t=t₁ and t=t₂ is:
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Position is x = At³ + Bt² + Ct + D. The average acceleration between t=t₁ and t=t₂ is:

G1 Physics · Accepted Answer

Velocity is v = 3At² + 2Bt + C. Thus average acceleration = [v(t₂)−v(t₁)]/(t₂−t₁) = [3A(t₂²−t₁²)+2B(t₂−t₁)]/(t₂−t₁) = 3A(t₁+t₂)+2B.