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vernier callipers and screw gauge questions with solutions
Practice Unit dimension and error for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
Showing 1–10 of 65 questions
- MCQeasyUnit dimension and errorOpen question & full solution →
A screw gauge has pitch 1 mm and 100 divisions on its circular scale. Its least count is:
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- Multi-correctdifficultUnit dimension and error
A student wants to determine the density of a small solid sphere as accurately as possible using a balance and a vernier calipers. Which steps are appropriate?
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JEE MainsNEET
Open question & full solution → - MCQdifficultUnit dimension and error
A spherical metal ball has mass 65.4 g. Its diameter is measured using a vernier calipers with 20 VSD = 19 MSD and 1 MSD = 1 mm. The main scale reading is 24 mm, the 14th vernier division coincides, and the zero error is -0.10 mm. Taking π = 3.14, the density of the ball is closest to:
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JEE MainsNEET
Open question & full solution → - MCQmediumUnit dimension and error
Figure 1 shows the main-scale and Vernier-scale configuration before measurement. Figure 2 shows the configuration while measuring the diameter D of a tube. The measured value of D is:

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JEE Advanced 2025 Paper 1
Open question & full solution → - MCQdifficultUnit dimension and error
A screw gauge has pitch p and 80 circular-scale divisions. Its least count is 0.004 mm. If the screw advances through 3.2 mm in a certain number of complete rotations, that number is:
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JEE MainsNEET
Open question & full solution → - MCQdifficultUnit dimension and error
A student measures the diameter of a pendulum bob with a vernier calipers and the distance from the point of suspension to the lower end of the bob with a metre scale. The corrected bob diameter is 2.64 cm and the suspension-to-lower-end distance is 102.8 cm. The effective pendulum length is:
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JEE MainsNEET
Open question & full solution → - Multi-correctdifficultUnit dimension and error
The least counts of two instruments are LC₁ = 0.02 mm and LC₂ = 0.005 mm. Which statements are correct?
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JEE MainsNEET
Open question & full solution → - IntegerdifficultUnit dimension and error
A direct vernier has N VSD = (N - 4) MSD. If 1 MSD = 0.5 mm and the least count is 0.02 mm, find N.
JEE MainsNEET
Open question & full solution → - MCQdifficultUnit dimension and error
A wire of length 2.0 m and resistivity 1.7 × 10⁻⁸ Ω m is measured by a screw gauge. The pitch is 0.5 mm and the circular scale has 100 divisions. The pitch-scale reading is 0.50 mm, the 26th circular division coincides, and the zero error is -0.01 mm. The resistance of the wire is closest to:
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JEE MainsNEET
Open question & full solution → - MCQeasyUnit dimension and error
10 divisions on the main scale of a Vernier caliper coincide with 11 divisions on the Vernier scale. If each division on the main scale is of 5 units, the least count of the instrument is:
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JEE Mains 2024 01 Feb Morning Shift
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