Figure 1 shows the main-scale and Vernier-scale configuration before measurement. Figure 2 shows the configuration while measuring the diameter D of a tube. The measured value of D is:

Question

G1 Physics · Accepted Answer

From Fig. 1 the zero correction is zero. In Fig. 2, Main-scale reading = 0.10 cm, Vernier contribution = 0.03 cm. Therefore D = 0.10 + 0.03 = 0.13 cm. Hence option C is correct.