Resistance of a wire at 0°C, 100°C and t°C is found to be 10 Ω, 10.2 Ω and 10.95 Ω respectively. The temperature t in Kelvin scale i s______.

Question

G1 Physics · Accepted Answer

Resistance relation: R = R₀(1 + αΔT) For 0°C to 100°C: (10.2 - 10)/10 = α(100) Therefore: α = 0.2/(1000) For 0°C to t°C: (10.95 - 10)/10 = αt Dividing the two relations: t/100 = 0.95/0.2 t = 475°C In Kelvin: T = 475 + 273 = 748 K