In a Young's double-slit experiment, the phase differences at points P and Q are π/3 and π/2 respectively. The two interfering waves have equal amplitude. The ratio $I_{P}$ : $I_{Q}$ is:
Options

Question

In a Young's double-slit experiment, the phase differences at points P and Q are π/3 and π/2 respectively. The two interfering waves have equal amplitude. The ratio $I_{P}$ : $I_{Q}$ is:

Options

G1 Physics · Accepted Answer

For equal slit intensities I₀, I = 4I₀ cos²(φ/2) At P, φ = π/3: I(P) = 4I₀ cos²(π/6) = 4I₀( 3 4 \frac{3}{4} 4 3 ​ ) = 3I₀ At Q, φ = π/2: I(Q) = 4I₀ cos²(π/4) = 4I₀(1/2) = 2I₀ Therefore, I(P):I(Q) = 3:2 Hence option A follows.

In a Young's double-slit experiment, the phase differences at points P and Q are π/3 and π/2 respectively. The two interfering waves have equal amplitude. The ratio I P I_{P} I P ​ : I Q I_{Q} I Q ​ is:

In a Young's double-slit experiment, the phase differences at points P and Q are π/3 and π/2 respectively. The two interfering waves have equal amplitude. The ratio I P I_{P} I P : I Q I_{Q} I Q is: