A positively charged sphere of radius r₀ carries a volume charge density ρ (Figure). A spherical cavity of radius r₀/2 is then scooped out and left empty, as shown. What is the direction and magnitude of the electric field at point B ?

Question

G1 Physics · Accepted Answer

Step 1: Convert the density to charge using dq = ρ dV, dq = λ dl, or dq = σ dA as appropriate. Step 2: Integrate over the stated region and then use Coulomb's law/Gauss's law for the field or flux. Step 3: Apply the given radius/position limits and simplify. Final: Option A. In this specific setup, apply the calculation to: A positively charged sphere of radius r₀ carries a volume charge density ρ (Figure). A spherical cavity o.