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JEE Advanced 2025 Paper 1 physics questions with solutions
Browse JEE Advanced 2025 Paper 1 Physics questions with solutions. Useful for JEE, NEET, and school exam revision.
Showing 1–10 of 16 questions
- NumericdifficultElectromagnetic wave
A cube of unit volume contains 35 × 10⁷ photons of frequency 10¹⁵ Hz. Treating their total energy as the average electromagnetic-wave energy in the same volume, the magnetic-field amplitude is α × 10⁻⁹ T. Given μ₀ = 4π × 10⁻⁷ T m A⁻¹, h = 6 × 10⁻³⁴ J s and π = 22/7, find α.
JEE Advanced 2025 Paper 1
Open question & full solution → - Multi-correctdifficultWave Motion
Three strings S₁, S₂ and S₃ have linear mass densities μ, 4μ and 16μ, respectively, and are connected in series as shown. A generator sends y = y₀ cos(ωt - kx) along S₁. Which statements are correct?

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JEE Advanced 2025 Paper 1
Open question & full solution → - MatchdifficultAC Circuits
An AC source V(t) = 300 sin(400t) V is connected to each load in List-I. Match each load with the corresponding current-time graph in List-II.

List 1




.
List 2
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JEE Advanced 2025 Paper 1
Open question & full solution → - Multi-correctdifficultElectromagnetic Induction
A conducting square loop of side L, mass M and resistance R enters a region y ≥ 0 containing uniform magnetic field B = B₀ k̂ with initial velocity v₀ ĵ. Define K = B₀²L²/(RM). Ignoring self-inductance and gravity, which statements are correct?
Image
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JEE Advanced 2025 Paper 1
Open question & full solution → - MCQdifficultElectromagnetic Induction
A conducting square loop initially lies in the XZ plane with its lower edge hinged along the X-axis. Only in the region y ≥ 0 there is a time-dependent magnetic field B(t) = B₀ cos(ωt) k̂. At t = 0 the loop starts rotating with angular speed ω about the X-axis in the clockwise direction as viewed from +X. Ignoring self-inductance and gravity, choose the correct induced e.m.f. V versus time graph.

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JEE Advanced 2025 Paper 1
Open question & full solution → - MCQmediumUnit dimension and error
Figure 1 shows the main-scale and Vernier-scale configuration before measurement. Figure 2 shows the configuration while measuring the diameter D of a tube. The measured value of D is:

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JEE Advanced 2025 Paper 1
Open question & full solution → - MatchdifficultElectrostatic
Four configurations of two ideal electric dipoles are shown in List-I. Each dipole has magnitude p and the dipoles are 2r apart along x. X is the midpoint. Match each configuration with the resultant electric field at X.
Image
List 1




.
List 2
1. E = 0
2. E = -p ĵ/(2πε₀r³)
3. E = -p(î - ĵ)/(4πε₀r³)
4. E = p(2î - ĵ)/(4πε₀r³)
5. E = p î/(πε₀r³)
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JEE Advanced 2025 Paper 1
Open question & full solution → - MatchdifficultNuclear physics
Match the functional dependence of energy E on atomic number Z in List-I with the appropriate phenomenon in List-II.
List 1
P. E ∝ Z²
Q. E ∝ (Z - 1)²
R. E ∝ Z(Z - 1)
S. E is practically independent of Z
.
List 2
1. Energy of characteristic x-rays
2. Electrostatic part of nuclear binding energy for stable nuclei with mass numbers 30 to 170
3. Energy of continuous x-rays
4. Average nuclear binding energy per nucleon for stable nuclei with mass numbers 30 to 170
5. Energy of radiation from electronic transitions in hydrogen-like atoms
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JEE Advanced 2025 Paper 1
Open question & full solution → - NumericmediumSimple Harmonic Motion
A person in an elevator weighs a 50 kg object. The height of the elevator is y = 8[1 + sin(2πt/T)] m, where T = 40π s. Taking g = 10 m s⁻², find the maximum variation of the object's observed weight in newtons.
JEE Advanced 2025 Paper 1
Open question & full solution → - MCQdifficultCenter of maas , Momentum and Collision
In a scattering experiment, a particle of mass 2m collides elastically with a particle of mass m initially at rest. The maximum angular deviation θ of the heavier particle is:

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JEE Advanced 2025 Paper 1
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