An object is moving with velocity 2î + 3ĵ + 6k̂ m s⁻¹. A plane mirror whose reflecting surface is parallel to the y-z plane is moving with velocity î + ĵ + k̂ m s⁻¹. What is the velocity of the image as seen by a stationary observer?
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Question

An object is moving with velocity 2î + 3ĵ + 6k̂ m s⁻¹. A plane mirror whose reflecting surface is parallel to the y-z plane is moving with velocity î + ĵ + k̂ m s⁻¹. What is the velocity of the image as seen by a stationary observer?

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G1 Physics · Accepted Answer

For a plane mirror parallel to the y-z plane, only the x-coordinate is reflected. Thus vₓ(image)=2vₓ(mirror)-vₓ(object)=2(1)-2=0. The y and z components remain those of the object: 3 and 6. Hence the image velocity is 3ĵ + 6k̂ m s⁻¹.